shanshanzhong
eb414749c3
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原 compare > 0 要求严格大于阈值，导致 header=1.0.0 被判为老版本， 去掉最后一个套餐后列表为空。改为 >= 0，有 header 且版本 >= 阈值均视为新版本。 Co-Authored-By: claude-flow <ruv@ruv.net>
84 lines
1.4 KiB
Go
84 lines
1.4 KiB
Go
package apiversion
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import (
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"regexp"
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"strconv"
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"strings"
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)
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const DefaultThreshold = "1.0.0"
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type Version struct {
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Major int
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Minor int
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Patch int
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}
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var versionPattern = regexp.MustCompile(`^v?(\d+)\.(\d+)\.(\d+)$`)
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func Parse(header string) (Version, bool) {
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normalized := strings.TrimSpace(header)
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if normalized == "" {
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return Version{}, false
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}
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matches := versionPattern.FindStringSubmatch(normalized)
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if len(matches) != 4 {
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return Version{}, false
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}
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major, err := strconv.Atoi(matches[1])
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if err != nil {
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return Version{}, false
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}
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minor, err := strconv.Atoi(matches[2])
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if err != nil {
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return Version{}, false
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}
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patch, err := strconv.Atoi(matches[3])
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if err != nil {
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return Version{}, false
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}
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return Version{Major: major, Minor: minor, Patch: patch}, true
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}
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func UseLatest(header string, threshold string) bool {
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currentVersion, ok := Parse(header)
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if !ok {
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return false
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}
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thresholdVersion, ok := Parse(strings.TrimSpace(threshold))
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if !ok {
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thresholdVersion, _ = Parse(DefaultThreshold)
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}
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return compare(currentVersion, thresholdVersion) >= 0
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}
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func compare(left Version, right Version) int {
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if left.Major != right.Major {
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if left.Major > right.Major {
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return 1
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}
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return -1
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}
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if left.Minor != right.Minor {
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if left.Minor > right.Minor {
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return 1
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}
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return -1
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}
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if left.Patch != right.Patch {
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if left.Patch > right.Patch {
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return 1
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}
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return -1
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}
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return 0
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}
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